x^2-227x+225=0

Solution for x^2-227x+225=0 equation:

x^2-227x+225=0

a = 1; b = -227; c = +225;
Δ = b2-4ac
Δ = -2272-4·1·225
Δ = 50629
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-227)-\sqrt{50629}}{2*1}=\frac{227-\sqrt{50629}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-227)+\sqrt{50629}}{2*1}=\frac{227+\sqrt{50629}}{2}
$